Answer by Eric Postpischil for C Pre-Processor Macro code with () and {}
For c, the initializer is an expression, and its value is 3. For d, the initializer is a list in braces, and it provides too many values, of which only the first is used.After macro expansion, the...
View ArticleAnswer by P.P for C Pre-Processor Macro code with () and {}
In addition to other answers,unsigned int d = {1,2,3};(after macro substitution)is not valid in C. It violates 6.7.9 Initialization:No initializer shall attempt to provide a value for an object not...
View ArticleAnswer by Afshin for C Pre-Processor Macro code with () and {}
Remember, pre-processor just replaces macros. So in your case you code will be converted to this:#include <stdio.h>int main(){ unsigned int c = (1,2,3); unsigned int d = {1,2,3};...
View ArticleC Pre-Processor Macro code with () and {}
#include <stdio.h>#define a (1,2,3)#define b {1,2,3}int main(){ unsigned int c = a; unsigned int d = b; printf("%d\n",c); printf("%d\n",d); return 0;}Above C code will print output as 3 and 1.But...
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